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Dual Nature of Matter

JEE Main level, single correct, medium

105 of 200

Question 105 of 200

In an experiment with photoelectric effect, the stopping potential,

Show answer and solution

Answer: (D) is $\left(\frac{1}{\mathrm{e}}\right)$ times the maximum kinetic energy of the emitted photoelectrons

From Einstein photoelectric equation

\frac{h c}{\lambda}=\phi+e V_S

Maximum K.E.

=(\mathrm{K})_{\max }=e V s

So,

V_S=\frac{(\mathrm{K})_{\max }}{e}

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JEE Main 2025 Apr 2 Shift 1 question paper

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