Dual Nature of Matter

JEE Main level, single correct, medium

123 of 200

Question 123 of 200

If the total energy transferred to a surface in time tt is 6.48×105J6.48\times {10}^{5}J, then the magnitude of the total momentum delivered to this surface for complete absorption will be :

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Answer: (B) 2.16×10−3kgms−12.16\times {10}^{-3}kgm{s}^{-1}

As we know,
p=Ec,p=\dfrac{E}{c}, where cc is velocity of light.
Therefore, p=6.48×1053×108=2.16×10−3kgms−1p=\dfrac{6.48\times {10}^{5}}{3\times {10}^{8}}=2.16\times {10}^{-3}kgm{s}^{-1}

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