Dual Nature of Matter

JEE Main level, single correct, medium

174 of 200

Question 174 of 200

When a certain photosensitive surface is illuminated with a monochromatic light of frequency ν,\nu , the stopping potential of the photo current is −V02.-\dfrac{{V}_{0}}{2}. When the surface is illuminated by monochromatic light of frequency ν2,\dfrac{\nu }{2}, the stopping potential is −V0.-{V}_{0}. The threshold frequency for photoelectric emission is

Show answer and solution

Answer: (B) 3v2\dfrac{3v}{2}

hν​=W+V02eh\nu ​=W+\dfrac{{V}_{0}}{2}e

hν​2=W+V0e\dfrac{h\nu ​}{2}=W+{V}_{0}e

On solving, we get, W=32hν​W=\dfrac{3}{2}h\nu ​

⇒hν​0=32hν​\Rightarrow h{\nu ​}_{0}=\dfrac{3}{2}h\nu ​

⇒ν​0=32ν​\Rightarrow {\nu ​}_{0}=\dfrac{3}{2}\nu ​

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Photoelectric effect and matter waves simulationDrag the sliders and watch the numbers in this question change.Revise Modern Physics firstFormula sheet, solved examples and the traps students fall into.

More Physics practice

JEE Main Physics practice question on Dual Nature of Matter (Photoelectric Effect), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.