Electromagnetic Induction

JEE Main level, single correct, medium

140 of 153

Question 140 of 153

Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross sectional area A=A= 10 cm210 \mathrm{~cm}^2 and length =20 cm=20 \mathrm{~cm}. If one of the solenoids has 300 turns and the other 400 turns, their mutual inductance is (μ0=4π×10−7TmA−1)\left(\mu_0=4 \pi \times 10^{-7} \mathrm{Tm} \mathrm{A}^{-1}\right)

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Answer: (D) 2.4π×10−4H2.4 \pi \times 10^{-4} \mathrm{H}

M=μ0N1N2Aℓ=2.4π×10−4HM=\frac{\mu_0 N_1 N_2 A}{\ell}=2.4 \pi \times 10^{-4} \mathrm{H}

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