Electromagnetic Induction

JEE Main level, single correct, medium

152 of 153

Question 152 of 153

An ideal coil of 10H10 \mathrm{H} is connected in series with a resistance of 5Ω5 \Omega and a battery of 5 V5 \mathrm{~V}.
22 second after the connection is made the current flowing in amperes in the circuit is

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Answer: (D) (1−e−1)\left(1-\mathrm{e}^{-1}\right)

i=i0(1−eRtL)\mathrm{i}=\mathrm{i}_0\left(1-\mathrm{e}^{\frac{\mathrm{Rt}}{\mathrm{L}}}\right)
=(1−e−1)=\left(1-\mathrm{e}^{-1}\right)

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