Electromagnetic Induction

JEE Main level, single correct, medium

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Question 153 of 153

A coil of inductance 300mH300 \mathrm{mH} and resistance 2Ω2 \Omega is connected to a source of voltage 2V. The current reaches half of its steady state value in

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Answer: (B) 0.1 s0.1 \mathrm{~s}

I=I∘(1−e−RLt)\mathrm{I}=\mathrm{I}_{\circ}\left(1-\mathrm{e}^{-\frac{\mathrm{R}}{\mathrm{L}}\mathrm{t}}\right)
0.693=RLt0.693=\frac{\mathrm{R}}{\mathrm{L}} \mathrm{t}
t=.3×0.6932=0.1sec\mathrm{t}=\frac{.3 \times 0.693}{2}=0.1 \mathrm{sec}

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