Electromagnetic Waves

JEE Main level, single correct, medium

26 of 165

Question 26 of 165

A plane electromagnetic wave of frequency 20 MHz travels in free space along the +x+x direction. At a particular point in space and time, the electric field vector of the wave is Ey=9.3Vm−1\mathrm{E}_y=9.3 \mathrm{Vm}^{-1}. Then, the magnetic field vector of the wave at that point is

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Answer: (B) Bz=3.1×10−8 T\mathrm{B}_z=3.1 \times 10^{-8} \mathrm{~T}

E=BC9.3=B×3×108 B=9.33×108=3.1×10−8 T\begin{aligned} & \mathrm{E}=\mathrm{BC} \\ & 9.3=\mathrm{B} \times 3 \times 10^8 \\ & \mathrm{~B}=\frac{9.3}{3 \times 10^8}=3.1 \times 10^{-8} \mathrm{~T}\end{aligned}

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