Electromagnetic Waves

JEE Main level, single correct, medium

53 of 165

Question 53 of 165

Match List I and List II A Gauss’s Law in Electrostatics I ∮E⃗⋅dl⃗=−dϕBdt\oint \vec{E}\cdot \vec{dl}=-\dfrac{d{\phi }_{B}}{dt} B Faraday's Law II ∮B⃗⋅dA⃗=0\oint \vec{B}\cdot d\vec{A}=0 C Gauss’s Law in Magnetism III ∮B⃗⋅dl⃗=μ0ic+μ0∈0dϕEdt\oint \vec{B}\cdot d\vec{l}={\mu }_{0}{i}_{c}+{\mu }_{0}{\in }_{0}\dfrac{d{\phi }_{E}}{dt} D Ampere-Maxwell Law IV ∮E⃗⋅ds⃗=q∈0\oint \vec{E}\cdot d\vec{s}=\dfrac{q}{{\in }_{0}} Choose the correct answer from the options given below :

Show answer and solution

Answer: (A) A-IV, B-I, C-II, D-III

(A) Gauss law states that the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. So, ϕ=∮E⃗⋅ds⃗=q∈0\phi =\oint \vec{E}\cdot d\vec{s}=\dfrac{q}{{\in }_{0}}
(B) Faraday’s law explains that the direction of the current will be opposite to the direction of flux that produced it, so ∮E⃗⋅dl⃗=−dϕBdt\oint \vec{E}\cdot d\vec{l}=-\dfrac{d{\phi }_{B}}{dt}
(C) Gauss's law for magnetism states that the magnetic flux B across any closed surface is zero, so ∮B⃗⋅dA⃗=0\oint \vec{B}\cdot d\vec{A}=0
(D) Ampere’s Maxwell law is stated as
∮B⃗⋅dl⃗=μ0ic+μ0∈0dϕEdt\oint \vec{B}\cdot d\vec{l}={\mu }_{0}{i}_{c}+{\mu }_{0}{\in }_{0}\dfrac{d{\phi }_{E}}{dt}
Where ic={i}_{c}=Conduction current and
∈0dϕEdt={\in }_{0}\dfrac{d{\phi }_{E}}{dt}=Displacement current
Thus, A-IV, B-I, C-II, D-III

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.

More Physics practice

JEE Main Physics practice question on Electromagnetic Waves (Electromagnetic Waves and Maxwell's equations), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.