Electromagnetic Waves

JEE Main level, single correct, medium

94 of 165

Question 94 of 165

The magnetic field of a plane electromagnetic wave is B⃗=3×10−8sin⁡[200π(y+ct)]i^T\vec{B}=3\times {10}^{-8}\sin \left[200\pi (y+ct)\right]\hat{i}T . Where, c=3×108ms−1c=3\times {10}^{8}m{s}^{-1} is the speed of light the corresponding electric filed is :

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Answer: (A) E⃗=9sin⁡[200π(y+ct)k^V/m\vec{E}=9\sin [200\pi (y+ct)\hat{k}V/m

E0=cB0{E}_{0}=c{B}_{0}
∴E⃗×B⃗‖C⃗⇒k^×i^=j^∴\vec{E}\times \vec{B}‖\vec{C}\Rightarrow \hat{k}\times \hat{i}=\hat{j}
E⃗=3×108×3×10−8sin⁡[200π(y+ct)(−k^)=9sin⁡[200π(y+ct)](−k^)\vec{E}=3\times {10}^{8}\times 3\times {10}^{-8}\sin [200\pi \left(y+ct\right)(-\hat{k}) =9\sin [200\pi \left(y+ct\right)](-\hat{k})

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