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A monochromatic beam of light has a frequency v=(3)/(2 π) × 10^12 ~Hz and is propagating along the direction i+j√(2). It is polarized along the k direction. The acceptable form for the magnetic field is:

(E0)/(C) ( i-j√(2) ) [10^4 ( i-j√(2) ) · r- (3 × 10^12 ) t ]

(E0)/(C) ( i-j√(2) ) [10^4 ( i+j√(2) ) · r- (3 × 10^12 ) t ]

(E0)/(C) k [10^4 ( i+j√(2) ) r+ (3 × 10^12 ) t ]

(E0)/(C) (i+j+k)√(3) [10^4 ( i+j√(2) ) r+ (3 × 10^12 ) t ]

Electromagnetic Waves

JEE Main level, single correct, medium

118 of 165

Question 118 of 165

A monochromatic beam of light has a frequency $v=\frac{3}{2 \pi} \times 10^{12} \mathrm{~Hz}$ and is propagating along the direction $\frac{\hat{i}+\hat{j}}{\sqrt{2}}$ . It is polarized along the $\hat{k}$ direction. The acceptable form for the magnetic field is:

Show answer and solution

Answer: (A) $\frac{E_0}{C}\left(\frac{\hat{i}-\hat{j}}{\sqrt{2}}\right) \cos \left[10^4\left(\frac{\hat{i}-\hat{j}}{\sqrt{2}}\right) \cdot \vec{r}-\left(3 \times 10^{12}\right) t\right]$

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