Electromagnetic Waves

JEE Main level, single correct, medium

162 of 165

Question 162 of 165

An X-ray tube is operated at 1.241.24 million volt. The shortest wavelength of the produced photon will be:

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Answer: (A) 10−3nm{10}^{-3}nm

λmin⁡=1240ΔV(nm){\lambda }_{\min }=\dfrac{1240}{\Delta V}\left(nm\right)
=12401.24×106=10−3nm=\dfrac{1240}{1.24\times {10}^{6}}={10}^{-3}nm

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