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Experimental Physics

JEE Main level, single correct, medium

5 of 70

Question 5 of 70

In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division $=0.05 \mathrm{~mm}$ , then the least count of the vernier callipers is $\_\_\_\_$ mm.

Show answer and solution

Answer: (C) 0.002

Given: 50 vernier divisions = 48 main divisions and 1 main division = 0.05 mm
50 vernier divisions = 48 × 0.05 = 2.4 mm
1 vernier division = 2.4/50 = 0.048 mm
Least count = 1 main division - 1 vernier division = 0.05 - 0.048 = 0.002 mm

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JEE Main Physics practice question on Experimental Physics (Experimental Physics), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division =0.05 mm=0.05 \mathrm{~mm}=0.05 mm, then the least count of the vernier callipers is ____\_\_\_\_____ mm.

JEE Main question paper PDF

More Physics practice

In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division $=0.05 \mathrm{~mm}$ , then the least count of the vernier callipers is $\_\_\_\_$ mm.