Experimental Physics

JEE Main level, single correct, medium

6 of 70

Question 6 of 70

In a screw gauge, the zero of the circular scale lies 3 divisions above the horizontal pitch line when their metallic studs are brought in contact. Using this instrument thickness of a sheet is measured. If pitch scale reading is 1 mm and the circular scale reading is 51 then the correct thickness of the sheet is ____\_\_\_\_ mm.
[Assume least count is 0.01 mm ]

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Answer: (C) 1.541.54

For a screw gauge, the measurement formula is: Reading = Pitch scale + (Circular scale × Least count) - Zero error
The zero of circular scale lies 3 divisions above the pitch line, indicating negative zero error:

Zero error = -3 × 0.01 = -0.03 mm

Reading = 1 + (51 × 0.01) - (-0.03) = 1 + 0.51 + 0.03 = 1.54 mm

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