Mathematics in Physics

JEE Main level, single correct, medium

8 of 121

Question 8 of 121

The angle between vector Q⃗\vec{Q} and the resultant of (2Q⃗+2P⃗)(2 \vec{Q}+2 \vec{P}) and (2Q⃗−2P⃗)(2 \vec{Q}-2 \vec{P}) is :

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Answer: (B) 0∘0^{\circ}

$\begin{aligned}
& \overrightarrow{\mathrm{R}}=(2 \overrightarrow{\mathrm{Q}}+2 \overrightarrow{\mathrm{P}})+(2 \overrightarrow{\mathrm{Q}}-2 \overrightarrow{\mathrm{P}}) \\
& \overrightarrow{\mathrm{R}}=4 \overrightarrow{\mathrm{Q}}
\end{aligned}$
Angle between Q⃗\vec{Q} and R⃗\vec{R} is zero.

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