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Mathematics in Physics

JEE Main level, single correct, medium

12 of 121

Question 12 of 121

Three forces ${F}_{1}=10N,{F}_{2}=8N,{F}_{3}=6N$ are acting on a particle of mass $5kg$ . The forces ${F}_{2}$ and ${F}_{3}$ are applied perpendicularly so that particle remains at rest. If the force ${F}_{1}$ is removed, then the acceleration of the particle is

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Answer: (D) $2m{s}^{–2}$

When the force

{F}_{1}

is removed, the particle starts accelerating because of the resultant force between

{F}_{2}

and

{F}_{3}

.
The resultant force can be calculated as follows:

\begin{matrix}F & = & \sqrt{{{F}_{2}}^{2}+{{F}_{3}}^{2}} \\ & = & 10N\end{matrix}

Hence, the acceleration of the particle is given by

\begin{matrix}a & = & \dfrac{10N}{5kg} \\ & = & 2m{s}^{–2}\end{matrix}

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