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Mathematics in Physics

JEE Main level, numerical answer, medium

47 of 121

Question 47 of 121

If $\vec{A}=\left(2\hat{i}+3\hat{j}-\hat{k}\right)m$ and $\vec{B}=\left(\hat{i}+2\hat{j}+2\hat{k}\right)m$ . The magnitude of component of vector $\vec{A}$ along vector $\vec{B}$ will be _____ $m$ .

Show answer and solution

Answer: 2

GIven vector are

\vec{A}=\left(2\hat{i}+3\hat{j}-\hat{k}\right)m

and

\vec{B}=\left(\hat{i}+2\hat{j}+2\hat{k}\right)m

Component of

\vec{A}

along

\vec{B}=\vec{A}\cdot \hat{B}

=\dfrac{\vec{A}\cdot \vec{B}}{\left|\vec{B}\right|}=\dfrac{2+6-2}{\sqrt{{1}^{2}+{2}^{2}+{2}^{2}}}

=\dfrac{6}{3}=2

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

JEE Main Physics practice question on Mathematics in Physics (Multiplication of Vectors), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

If A⃗=(2i^+3j^−k^)m\vec{A}=\left(2\hat{i}+3\hat{j}-\hat{k}\right)mA=(2i^+3j^​−k^)m and B⃗=(i^+2j^+2k^)m\vec{B}=\left(\hat{i}+2\hat{j}+2\hat{k}\right)mB=(i^+2j^​+2k^)m. The magnitude of component of vector A⃗\vec{A}A along vector B⃗\vec{B}B will be _____ mmm.

JEE Main question paper PDF

More Physics practice

If $\vec{A}=\left(2\hat{i}+3\hat{j}-\hat{k}\right)m$ and $\vec{B}=\left(\hat{i}+2\hat{j}+2\hat{k}\right)m$ . The magnitude of component of vector $\vec{A}$ along vector $\vec{B}$ will be _____ $m$ .