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Mathematics in Physics

JEE Main level, single correct, medium

56 of 121

Question 56 of 121

In an experiment the values of two spring constants were measured as $k_{1}=(10 \pm 0.2) \mathrm{N} / \mathrm{m}$ and $k_{2}=(20 \pm 0.3) \mathrm{N} / \mathrm{m}$ . If these springs are connected in parallel, then the percentage error in equivalent spring constant is :

Show answer and solution

Answer: (B) 1.67%

For parallel combination:

k_{eq} = k_1 + k_2 = 10 + 20 = 30

N/m
For sum, absolute errors add:

\Delta k_{eq} = \Delta k_1 + \Delta k_2 = 0.2 + 0.3 = 0.5

N/m
Percentage error

= \frac{\Delta k_{eq}}{k_{eq}} \times 100 = \frac{0.5}{30} \times 100 = 1.67\%

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JEE Main 2025 Apr 2 Shift 1 question paper

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