Mathematics in Physics

JEE Main level, single correct, medium

80 of 121

Question 80 of 121

The maximum error in the measurement of resistance, current and time for which current flows in an electrical circuit are 11%,2% and 33% respectively. The maximum percentage error in the detection of the dissipated heat will be:

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Answer: (D) 88

Heat generated through resistance is given by, H=i2RtH={i}^{2}Rt
Therefore, the percentage error in the calculation can be found by,
⇒ΔHH×100=2×Δii×100+ΔRR×100+Δtt×100\Rightarrow \dfrac{\Delta H}{H}\times 100=2\times \dfrac{\Delta i}{i}\times 100+\dfrac{\Delta R}{R}\times 100+\dfrac{\Delta t}{t}\times 100
⇒ΔHH×100=4\Rightarrow \dfrac{\Delta H}{H}\times 100=4%+1%+3%
⇒ΔHH×100=8\Rightarrow \dfrac{\Delta H}{H}\times 100=8%

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