Mathematics in Physics

JEE Main level, single correct, medium

112 of 121

Question 112 of 121

A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be:

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Answer: (C) 92±2s92\pm 2s

T Ts{\text{T}}_{\text{s}} Ti−T{\text{T}}_{\text{i}}-\text{T} t1{\text{t}}_{1} 90 - 2 t2{\text{t}}_{2} 91 - 1 t3{\text{t}}_{3} 95 3 t4{\text{t}}_{4} 92 0 Ti{\text{T}}_{\text{i}} 92 Σ∣Ti−T∣N=1.5\dfrac{\Sigma {|T}_{i}-T|}{N}=1.5
Tr=92±1.5{T}_{r}=92\pm \text{1.5}

Tr=92±2{T}_{r}=92\pm 2

Because least count of clock is 1s

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