Question 101 of 192
The amount of work done to break a big water drop of radius ' ' into 27 small drops of equal radius is 10 J . The work done required to break the same big drop into 64 small drops of equal radius will be
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Answer: (A) 15 J
$\begin{aligned}
& W_1=s 4 \pi\left(\frac{R}{3}\right)^2 \times 27-4 \pi R^2 \cdot s \\
& \Rightarrow W_1=4 \pi R^2 \cdot s(2)=10 \text { Joule }
\end{aligned}$
Now,
& W_1=s 4 \pi\left(\frac{R}{3}\right)^2 \times 27-4 \pi R^2 \cdot s \\
& \Rightarrow W_1=4 \pi R^2 \cdot s(2)=10 \text { Joule }
\end{aligned}$
Now,