Fluid Mechanics

JEE Main level, single correct, medium

141 of 192

Question 141 of 192

A soap bubble, blown by a mechanical pump at the mouth of a tube increases in volume with time at a constant rate. The graph that correctly depicts the time dependence of pressure inside the bubble is given by:

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Answer: (D)

dVdt=k\dfrac{dV}{dt}=k

⇒V=kt\Rightarrow V=kt

⇒43πr3=kt\Rightarrow \dfrac{4}{3}\pi {r}^{3}=kt

⇒r=(3k4π)13t13\Rightarrow r={\left(\dfrac{3k}{4\pi }\right)}^{\dfrac{1}{3}}{t}^{\dfrac{1}{3}}

P−P0=4TrP-{P}_{0}=\dfrac{4T}{r}

⇒P−P0=4T.(3k4π)13.1t13\Rightarrow P-{P}_{0}=4T.{\left(\dfrac{3k}{4\pi }\right)}^{\dfrac{1}{3}}.\dfrac{1}{{t}^{\dfrac{1}{3}}}⇒P=4T.(3k4π)13.1t13+P0\Rightarrow P=4T.{\left(\dfrac{3k}{4\pi }\right)}^{\dfrac{1}{3}}.\dfrac{1}{{t}^{\dfrac{1}{3}}}+{P}_{0}

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