Kinematics

JEE Main level, single correct, medium

7 of 308

Question 7 of 308

A clock has 75 cm,60 cm75 \mathrm{~cm}, 60 \mathrm{~cm} long second hand and minute hand respectively. In 30 minutes duration the tip of second hand will travel xx distance more than the tip of minute hand. The value of xx in meter is nearly (Take π=3.14\pi=3.14 ) :

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Answer: (C) 139.4

xmin⁡=π×rmin⁡=π×60100 m.xsecond =30×2π×rsecond =30×2π×75100x=xsecond −xmin⁡=139.4 m\begin{aligned} \mathrm{x}_{\min }= & \pi \times \mathrm{r}_{\min } \\ = & \pi \times \frac{60}{100} \mathrm{~m} . \\ \mathrm{x}_{\text {second }} & =30 \times 2 \pi \times \mathrm{r}_{\text {second }} \\ & =30 \times 2 \pi \times \frac{75}{100} \\ \mathrm{x}= & \mathrm{x}_{\text {second }}-\mathrm{x}_{\min } \\ = & 139.4 \mathrm{~m}\end{aligned}

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