Kinematics

JEE Main level, single correct, medium

11 of 308

Question 11 of 308

A body travels 102.5 m102.5 \mathrm{~m} in nth \mathrm{n}^{\text {th }} second and 115.0 m115.0 \mathrm{~m} in (n+2)th (\mathrm{n}+2)^{\text {th }} second. The acceleration is :

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Answer: (A) 6.25 m/s26.25 \mathrm{~m} / \mathrm{s}^2

 Given, 102.5=u+a2(2n−1)&115=u+a2(2n+3)⇒102.5=u+an−a2&115=u+an+3a212.5=2a⇒a=6.25 m/s2\begin{aligned} & \text { Given, } 102.5=\mathrm{u}+\frac{\mathrm{a}}{2}(2 \mathrm{n}-1) \& \\ & 115=\mathrm{u}+\frac{\mathrm{a}}{2}(2 \mathrm{n}+3) \\ & \Rightarrow 102.5=\mathrm{u}+\mathrm{an}-\frac{\mathrm{a}}{2} \& \\ & 115=\mathrm{u}+\mathrm{an}+\frac{3 \mathrm{a}}{2} \\ & 12.5=2 \mathrm{a} \Rightarrow \mathrm{a}=6.25 \mathrm{~m} / \mathrm{s}^2 \end{aligned}

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