Kinematics

JEE Main level, single correct, medium

85 of 308

Question 85 of 308

The velocity-time graph of an object moving along a straight line is shown in figure. What is the distance covered by the object between t=0t=0 to t=4 st=4 \mathrm{~s} ?

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Answer: (A) 30 m30\mathrm{~m}

Distance travelled = displacement when direction of velocity remains constant
⇒ Distance = Area =12(2 s+4 s)(10 m/s)=30 m\begin{aligned} \Rightarrow \text { Distance } & =\text { Area } \\ & =\frac{1}{2}(2 \mathrm{~s}+4 \mathrm{~s})(10 \mathrm{~m} / \mathrm{s}) \\ & =30 \mathrm{~m}\end{aligned}

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