Kinematics

JEE Main level, single correct, medium

116 of 308

Question 116 of 308

A body is at rest at x=0x=0. At t=0t=0, it starts moving in the positive xx-direction with a constant acceleration. At the same instant another body passes through x=0x=0 moving in the positive xx direction with a constant speed. The position of the first body is given by x1(t)\mathrm{x}_1(\mathrm{t}) after time ' t\mathrm{t} ' and that of the second body by x2(t)x_2(t) after the same time interval. Which of the following graphs correctly describes (x1−x2)\left(x_1-x_2\right) as a function of time ' tt '?

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Answer: (B)

x1(t)=12at2x2(t)=vtx1−x2=12at2−vt\begin{aligned} & x_1(t)=\frac{1}{2} a t^2 \\ & x_2(t)=v t \\ & x_1-x_2=\frac{1}{2} a t^2-v t \end{aligned}

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