Kinematics

JEE Main level, numerical answer, medium

132 of 308

Question 132 of 308

The distance xx covered by a paritcle in one dimensional motion varies with time tt as x2=at2+2bt+c{x}^{2}=a{t}^{2}+2bt+c . If the acceleration of the particle depends on xx as x−n{x}^{-n} , where nn is an integer, the value of nn is _________

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Answer: 3

x2=at2+2bt+c{x}^{2}=a{t}^{2}+2bt+c
2xv=2at+2b2xv=2at+2b
xv=at+bxv=at+b
v2+ax=a{v}^{2}+ax=a
ax=a−(at+bx)2ax=a-{\left(\dfrac{at+b}{x}\right)}^{2}
a=a(at2+2bt+c)−(at+b)2x3a=\dfrac{a\left(a{t}^{2}+2bt+c\right)-{\left(at+b\right)}^{2}}{{x}^{3}}
a=ac−2x3a=\dfrac{a{c}^{-2}}{{x}^{3}}
aαx−3a\alpha {x}^{-3}

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