Question 176 of 308

A person standing on a spring balance inside a stationary lift measures $60kg$. The weight of that person if the lift descends with uniform downward acceleration of $1.8m{s}^{-2}$ will be $N$. $\left[g=10m{s}^{-2}\right]$

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Answer: 492

When lift is at rest
$N=mg$
$\Rightarrow 60\times 10=600N$
When lift moves with downward acceleration. In frame of lift pseudo force will be in upward direction.

${N}^{'}=M\left(g-a\right)$
$\Rightarrow 60\left(10-1.8\right)$
${N}^{'}\Rightarrow 492N$