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Kinematics

JEE Main level, single correct, medium

178 of 308

Question 178 of 308

An elevator in a building can carry a maximum of $10$ persons, with the average mass of each person being $68kg$ . The mass of the elevator itself is $920kg$ and it moves with a constant speed of $3m/s$ . The frictional force opposing the motion is $6000N$ . If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator $\left(g=10m/{s}^{2}\right)$ must be at least:

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Answer: (D) $66000W$

Net force on motor will be

{F}_{m}=\left[920+68\left(10\right)\right]g+6000

=22000N

So, required power for motor

{P}_{m}={\vec{F}}_{m}.\vec{v}

=22000\times 3

=66000watt

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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