Kinematics

JEE Main level, numerical answer, medium

199 of 308

Question 199 of 308

A gun mounted on the ground fires bullets in all directions with same speed. The farthest distance the bullets could reach is 6.46.4 m. The speed of the bullets from the gun is ______ m/s.
(take g=10g=10 m/s2^2)

Show answer and solution

Answer: 8

The maximum horizontal range of a projectile is given by Rmax=u2gR_{\text{max}} = \dfrac{u^2}{g}.

Given Rmax=6.4R_{\text{max}} = 6.4 m and g=10g = 10 m/s2^2.

Substituting the values:

6.4=u2106.4 = \dfrac{u^2}{10}

u2=64u^2 = 64

u=8u = 8 m/s.

Answer: 88

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