Kinematics

JEE Main level, single correct, medium

208 of 308

Question 208 of 308

The angle of projection of a particle is measured from the vertical axis as ϕ\phi and the maximum height reached by the particle is hmh_m. Here hmh_m as function of ϕ\phi can be presented as

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Answer: (C)


Hmax⁡=u2cos⁡2ϕ2 g\mathrm{H}_{\max }=\frac{\mathrm{u}^2 \cos ^2 \phi}{2 \mathrm{~g}}

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