Kinematics

JEE Main level, single correct, medium

213 of 308

Question 213 of 308

The angle of projection for a projectile to have same horizontal range and maximum height is :

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Answer: (A) tan⁡−1(4)\tan ^{-1}(4)

u2sin⁡2θg=u2sin⁡2θ2 g4sin⁡θcos⁡θ=sin⁡2θ4=tan⁡θ\begin{aligned} & \frac{\mathrm{u}^2 \sin 2 \theta}{\mathrm{g}}=\frac{\mathrm{u}^2 \sin ^2 \theta}{2 \mathrm{~g}} \\ & 4 \sin \theta \cos \theta=\sin ^2 \theta \\ & 4=\tan \theta\end{aligned}

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