Kinematics

JEE Main level, single correct, medium

304 of 308

Question 304 of 308

A bead of mass mm stays at point P(a,b)P\left(a,b\right) on a wire bent in the shape of a parabola y=4Cx2y=4C{x}^{2} and rotating with angular speed ω\omega (see figure). The value of ω\omega is (neglect friction)

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Answer: (A) 22gC2\sqrt{2gC}


mω2acosθ=mgsinθm{\omega }^{2}acos\theta =mgsin\theta
ω=gtan⁡θa\omega =\sqrt{\dfrac{g\tan \theta }{a}}
y=4cx2y=4c{x}^{2}
tan⁡θ=dydx=8xC\tan \theta =\dfrac{dy}{dx}=8xC
(tan⁡θ)a,b=8aC(\tan \theta {)}_{a,b}=8aC
ω=g×8aca=22gC\omega =\sqrt{\dfrac{g\times 8ac}{a}}=2\sqrt{2gC}

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