Question 12 of 295

A point source of light $S$, placed at a distance $60cm$ infront of the centre of a plane mirror of width $50cm$, hangs vertically on a wall. A man walks infront of the mirror along a line parallel to the mirror at a distance $1.2m$ from it (see in the figure). The distance between the extreme points where he can see the image of the light source in the mirror is__$cm$

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Answer: 150

$\tan \theta =\dfrac{25}{60}=\dfrac{x}{180}$
$x=75cm$
so distance between extreme point $=2x=2\times 75=150cm$