Ray Optics

JEE Main level, single correct, medium

35 of 295

Question 35 of 295

An object is placed beyond the centre of curvature CC of the given concave mirror. If the distance of the object is d1{d}_{1} from CC and the distance of the image formed is d2{d}_{2} from C,C, the radius of curvature of this mirror is:

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Answer: (B) 2d1d2d1−d2\dfrac{2{d}_{1}{d}_{2}}{{d}_{1}-{d}_{2}}

xy=f2xy={f}^{2}
(f+d1)(f−d2)=f2\left(f+{d}_{1}\right)\left(f-{d}_{2}\right)={f}^{2}
f=d1d2d1−d2f=\dfrac{{d}_{1}{d}_{2}}{{d}_{1}-{d}_{2}}
R=2f=2d1d2d1−d2R=2f=\dfrac{2{d}_{1}{d}_{2}}{{d}_{1}-{d}_{2}}

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