Question 78 of 295

A container contains a liquid with refractive index of 1.2 up to a height of 60 cm and another liquid having refractive index 1.6 is added to height H above first liquid. If viewed from above, the apparent shift in the position of bottom of container is 40 cm. The value of H is ______ cm.
(Consider liquids are immisible)

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Answer: 80

$y=$ apparent depth of bottom
$\frac{\mathrm{y}}{1}=\frac{\mathrm{H}}{1.6}+\frac{60}{1.2}$
Shift $=40$
$H+60-y=40$
$\mathrm{H}+60-\frac{\mathrm{H}}{1.6}-\frac{60}{1.2}=40$
$\frac{6}{16} \mathrm{H}=30$
$\mathrm{H}=80 \mathrm{~cm}$