Question 81 of 295

What is the lateral shift of a ray refracted through a parallel-sided glass slab of thickness ' $h$ ' in terms of the angle of incidence ' $i$ ' and angle of refraction ' $r$ ', if the glass slab is placed in air medium?

A$\frac{h \tan (i-r)}{\tan r}$B$\frac{h \sin (i-r)}{\cos r}$ChD$\frac{h \cos (i-r)}{\sin r}$

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Answer: (B) $\frac{h \sin (i-r)}{\cos r}$

$\begin{aligned} & A B=h \sec r \\ & B C=h \sec r \sin (\bar{i}-r) \\ & B C=\frac{h \sin (i-r)}{\cos r}\end{aligned}$