Ray Optics

JEE Main level, single correct, medium

98 of 295

Question 98 of 295

As shown in the figure, after passing through the medium 11. The speed of light v2{v}_{2} in medium 22 will be :
(Given c=3×108ms−1c=3\times {10}^{8}m{s}^{-1})

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Answer: (A) 1.0×108ms−11.0\times {10}^{8}m{s}^{-1}

The refractive index of a medium is given by, n=μrϵrn=\sqrt{{\mu }_{r}{\epsilon }_{r}}.
For medium 22, n2=1×9=3{n}_{2}=\sqrt{1\times 9}=3
Now speed of light in a medium will be,
cv=n⇒v=3×1083=1×108ms−1\dfrac{c}{v}=n \Rightarrow v=\dfrac{3\times {10}^{8}}{3}=1\times {10}^{8}m{s}^{-1}

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