Ray Optics

JEE Main level, numerical answer, medium

262 of 295

Question 262 of 295

A prism of angle A=1∘A=1^{\circ} μ=1.5\mu =1.5. A good estimate for the minimum angle of deviation (in degrees) is close to N10.\dfrac{N}{10}. Value of NN is ………\ldots \ldots \ldots

Show answer and solution

Answer: 5

Given,
Angle of prism, A=1∘A=1^{\circ}
Refractive index of prism, μ=1.5\mu =1.5
For this prism, minimum angle of deviation is given by
δ=(μ−1)A\delta =(\mu -1)A
⇒δ=(1.5−1)×1∘=12=510=N10\Rightarrow \delta =(1.5-1)\times 1^{\circ}=\dfrac{1}{2}=\dfrac{5}{10}=\dfrac{N}{10}
⇒N=5\Rightarrow N=5

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Lens ray diagram simulationDrag the sliders and watch the numbers in this question change.Revise Ray Optics firstFormula sheet, solved examples and the traps students fall into.

More Physics practice

JEE Main Physics practice question on Ray Optics (Prism and Dispersion of Light), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.