Rotational Motion

JEE Main level, numerical answer, medium

165 of 280

Question 165 of 280

The angular speed of truck wheel is increased from 900rpm900rpm to 2460rpm2460rpm in 2626 seconds. The number of revolutions by the truck engine during this time is ______.
(Assuming the acceleration to be uniform).

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Answer: 728

We know, θ=(ω1+ω22)t\theta =\left(\dfrac{{\omega }_{1}+{\omega }_{2}}{2}\right)t
Let number of revolutions be NN
∴2πN=2π(900+246060×2)×26∴2\pi N=2\pi \left(\dfrac{900+2460}{60\times 2}\right)\times 26
N=728N=728

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