Rotational Motion

JEE Main level, single correct, medium

168 of 280

Question 168 of 280

Two uniform circular discs are rotating independently in the same direction around their common axis passing through their centres. The moment of inertia and angular velocity of the first disc are 0.1kg−m20.1kg-{m}^{2} and 10rads−110\text{rad}{s}^{-1} respectively while those for the second one are 0.2kg−m20.2kg-{m}^{2}and 5rads−15rad{s}^{-1} respectively. At some instant they get stuck together and start rotating as a single system about their common axis with some angular speed. The kinetic energy of the combined system is :

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Answer: (B) 203J\dfrac{20}{3}J


Common angular velocity from angular momentum conversation

ω=l1ω1+I2ω2I1+I2=0.1×10+0.2×50.1+0.2=203\omega =\dfrac{{l}_{1}{\omega }_{1}+{I}_{2}{\omega }_{2}}{{I}_{1}+{I}_{2}}=\dfrac{0.1\times 10+0.2\times 5}{0.1+0.2}=\dfrac{20}{3}
Final K.E.

Kf=12I1ω2+12I2ω2{K}_{f}=\dfrac{1}{2}{I}_{1}{\omega }^{2}+\dfrac{1}{2}{I}_{2}{\omega }^{2}
=12(0.1+0.2)×(203)2⇒kf=203=\dfrac{1}{2}\left(0.1+0.2\right)\times {\left(\dfrac{20}{3}\right)}^{2}\Rightarrow {k}_{f}=\dfrac{20}{3}

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