Rotational Motion

JEE Main level, single correct, medium

258 of 280

Question 258 of 280

A sphere of mass 2kg2kg and radius 0.5m0.5m is rolling with an initial speed of 1ms−11{ms}^{-1} goes up an inclined plane which makes an angle of 30∘30^{\circ} with the horizontal plane, without slipping. How low will the sphere take to return to the starting point AA?

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Answer: (C) 0.56s0.56s

a=gsin⁡θ1+ImR2=57×102=257a=\dfrac{g\sin \theta }{1+\dfrac{I}{m{R}^{2}}}=\dfrac{5}{7}\times \dfrac{10}{2}=\dfrac{25}{7}
t=2v0a=2×1×725t=\dfrac{2{v}_{0}}{a}=\dfrac{2\times 1\times 7}{25}=0.56=0.56.

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