Question 272 of 280

A wheel is rolling on a plane surface. The speed of a particle on the highest point of the rim is $8 \mathrm{~m} / \mathrm{s}$. The speed of the particle on the rim of the wheel at the same level as the centre of wheel, will be :

A$4 \sqrt{2} \mathrm{~m} / \mathrm{s}$B$8 \mathrm{~m} / \mathrm{s}$C$4 \mathrm{~m} / \mathrm{s}$D$8 \sqrt{2} \mathrm{~m} / \mathrm{s}$

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Answer: (A) $4 \sqrt{2} \mathrm{~m} / \mathrm{s}$

If $V_B=2 V$
Point A is instantaneous center of rotation
Given $V_B=8 \mathrm{~m} / \mathrm{s}$
$\begin{aligned}
& \mathrm{V}=4 \mathrm{~m} / \mathrm{s} \\
& \mathrm{~V}_{\mathrm{p}}=\sqrt{2} \mathrm{v} \Rightarrow \mathrm{~V}_{\mathrm{p}}=4 \sqrt{2} \mathrm{~m} / \mathrm{s} \\
& \operatorname{correct}(1)
\end{aligned}$