Thermodynamics

JEE Main level, single correct, medium

7 of 190

Question 7 of 190

Match the LIST-I with LIST-II\text{Match the LIST-I with LIST-II} \[
\begin{array}{|l|p{6cm}|l|p{4cm}|}

\hline \textbf{LIST-I} & & \textbf{LIST-II} & \\

\hline A. & \text{Pressure varies inversely with volume of an ideal gas.} & I. & \text{Adiabatic process} \\

\hline B. & \text{Heat absorbed goes partly to increase internal energy and partly to do work.} & II. & \text{Isochoric process} \\

\hline C. & \text{Heat is neither absorbed nor released by a system.} & III. & \text{Isothermal process} \\

\hline D. & \text{No work is done on or by a gas.} & IV. & \text{Isobaric process} \\

\hline

\end{array}

\]

Choose the correct answer from the options given below:\text{Choose the correct answer from the options given below:}

Show answer and solution

Answer: (A) A-III, B-IV, C-I, D-II

$\begin{aligned}
& \mathrm{A} \rightarrow \mathrm{P} \propto \frac{1}{\mathrm{~V}} \\

& \Rightarrow \mathrm{PV}=\text { constant } \\

& \Rightarrow \mathrm{nRT}=\text { const. } \Rightarrow \mathrm{T}=\text { const. }

\end{aligned}$


Hence Isothermal III

B
→\rightarrow IV
W≠0,ΔU≠0,ΔQ≠0\mathrm{W} \neq 0, \Delta \mathrm{U} \neq 0, \Delta \mathrm{Q} \neq 0 [only isobaric]
C→IΔQ=0\mathrm{C} \rightarrow \mathrm{I} \Delta \mathrm{Q}=0 Adiabatic
D→\mathrm{D} \rightarrow II w =0=0 Isochoric
III, IV, I, II

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