Question 28 of 190

Using the given $\mathrm{P}-\mathrm{V}$ diagram, the work done by an ideal gas along the path ABCD is :

A$3 \mathrm{P}_0 \mathrm{~V}_0$B$-4 \mathrm{P}_0 \mathrm{~V}_0$C$-3 \mathrm{P}_0 \mathrm{~V}_0$D$4 \mathrm{P}_0 \mathrm{~V}_0$

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Answer: (C) $-3 \mathrm{P}_0 \mathrm{~V}_0$

Area under graph will be magnitude of graph and being counterclockwise graph it would be negative
$\begin{aligned}
& \text { Area }=2 P_0 \times V_0+P_0 V_0=3 P_0 V_0 \\
& \mathrm{~W}=-3 P_0 V_0
\end{aligned}$

JEE Main Physics practice question on Thermodynamics (First Law of Thermodynamics), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.