Thermodynamics

JEE Main level, single correct, medium

36 of 190

Question 36 of 190

Heat is given to an ideal gas in an isothermal process.
A. Internal energy of the gas will decrease.

B. Internal energy of the gas will increase.

C. Internal energy of the gas will not change.

D. The gas will do positive work.

E. The gas will do negative work.

Choose the correct answer from the options given below :

Show answer and solution

Answer: (D) C and D only

From the first law of thermodynamics, heat supplied to the system QQ, change in internal energy of the system ∆U∆U and work done by the system WW are related as:
Q=∆U+WQ=∆U+W
Since the process is isothermal, the temperature of the system is constant and therefore
∆U=0∆U=0 (i.e., internal energy is constant).
⇒Q=W\Rightarrow Q=W
As heat is supplied to the system,
QQ is positive and therefore WW is positive i.e., gas will do positive work.
Hence, correct options are C and D.

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.

More Physics practice

JEE Main Physics practice question on Thermodynamics (First Law of Thermodynamics), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.