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Thermodynamics

JEE Main level, numerical answer, medium

42 of 190

Question 42 of 190

One mole of an ideal gas at $27^{\circ}C$ is taken from $A$ to $B$ as shown in the given $PV$ indicator diagram. The work done by the system will be _______ $\times {10}^{-1}J.$ [Given, $R=8.3J{mole}^{-1}K,\ln 2=0.6931$ ] (Round off to the nearest integer)
(Round off to the nearest integer)

Show answer and solution

Answer: 17258

Process of isothermal

W=nRT\ell n\left(\dfrac{{V}_{2}}{{V}_{1}}\right)

=1\times 8.3\times 300\times \ln 2

=17258\times {10}^{-1}J

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Thermodynamics (First Law of Thermodynamics), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.