Thermodynamics

JEE Main level, single correct, medium

55 of 190

Question 55 of 190


The above P−VP-V diagram represents the thermodynamic cycle of an engine, operating with an ideal mono-atomic gas. The amount of heat, extracted from the source in a single cycle, is:

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Answer: (D) (132)P0V0\left(\dfrac{13}{2}\right){P}_{0}{V}_{0}

The heat is extracted from the source during the process A→BandB→CA\rightarrow BandB\rightarrow C
(∆Q)AB+(∆Q)BC{\left(∆Q\right)}_{AB}+{\left(∆Q\right)}_{BC}

=nCvdT+nCpdT=32P0V0+522P0V0=n{C}_{v}dT+n{C}_{p}dT=\dfrac{3}{2}{P}_{0}{V}_{0}+\dfrac{5}{2}2{P}_{0}{V}_{0}

=132P0V0=\dfrac{13}{2}{\text{P}}_{0}{\text{V}}_{0}

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