Thermodynamics

JEE Main level, single correct, medium

72 of 190

Question 72 of 190

Match List-I with List-II.
\(\begin{array}{|l|l|l|l|} \hline & \text{List - I} & & \text{List - II} \\ \hline \text { (A) } & \text { Isobaric } & \text { (I) } & \Delta Q=\Delta W \\ \hline \text { (B) } & \text { Isochoric } & \text { (II) } & \Delta Q=\Delta U \\ \hline \text { (C) } & \text { Adiabatic } & \text { (III) } & \Delta Q=\text { zero } \\ \hline \text { (D) } & \text { Isothermal } & \text { (IV) } & \Delta Q=\Delta U+P \Delta V \\ \hline \end{array}\)

ΔQ=\Delta \mathrm{Q}= Heat supplied
ΔW=\Delta \mathrm{W}= Work done by the system
ΔU=\Delta \mathrm{U}= Change in internal energy
P=\mathrm{P}= Pressure of the system
ΔV=\Delta \mathrm{V}= Change in volume of the system
Choose the correct answer from the options given below:

Show answer and solution

Answer: (C) (A)-(IV), (B)-(II), (C)-(III), (D)-(I)

(A) Isobaric (P=C)(\mathrm{P}=\mathrm{C})
ΔQ=ΔU+PΔ V\Delta \mathrm{Q}=\Delta \mathrm{U}+\mathrm{P} \Delta \mathrm{~V}
(B) Isochoric
(V=C)(\mathrm{V}=\mathrm{C})
ΔQ=ΔU\Delta \mathrm{Q}=\Delta \mathrm{U}
(C) Adiabatic
(ΔQ=0)(\Delta \mathrm{Q}=0)
ΔQ=0\Delta \mathrm{Q}=0
(D) Isothermal
(ΔU=0)(\Delta \mathrm{U}=0)
ΔQ=ΔW\Delta \mathrm{Q}=\Delta \mathrm{W}

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.

More Physics practice

JEE Main Physics practice question on Thermodynamics (Thermodynamic Processes), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.