Thermodynamics

JEE Main level, single correct, medium

88 of 190

Question 88 of 190

The heat absorbed by a system in going through the given cyclic process is :

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Answer: (B) 61.6 J61.6 \mathrm{~J}

ΔU=0( Cyclic process )ΔQ=W= area of P−V curve. =π×(140×103 Pa)×(140×10−6 m3)ΔQ=61.6 J\begin{aligned} & \Delta \mathrm{U}=0(\text { Cyclic process }) \\ & \Delta \mathrm{Q}=\mathrm{W}=\text { area of } \mathrm{P}-\mathrm{V} \text { curve. } \\ & =\pi \times\left(140 \times 10^3 \mathrm{~Pa}\right) \times\left(140 \times 10^{-6} \mathrm{~m}^3\right) \\ & \Delta \mathrm{Q}=61.6 \mathrm{~J}\end{aligned}

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