Thermodynamics

JEE Main level, numerical answer, medium

125 of 190

Question 125 of 190

In the reported figure, heat energy absorbed by a system in going through a cyclic process is ______πJ.\pi J.

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Answer: 100


For complete cyclic process

ΔU=0\Delta U=0
∴∴ from ΔQ=ΔU+W\Delta Q=\Delta U+W
=0+W=0+W
ΔQ=W\Delta Q=W
==Area
=πr1⋅r2=\pi {r}_{1}\cdot {r}_{2}
=π×(10×103)×(10×10−3)=\pi \times \left(10\times {10}^{3}\right)\times \left(10\times {10}^{-3}\right)
ΔQ=100π\Delta Q=100\pi
∴∴ Answer =100=100

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